Question

x^3+2x^2-16x-32/(x+2)(x+4)

Answer 1

$\frac{x^3+2x^2-16x-32}{(x+2)(x+4)} = \frac{(x^3-16x)+(2x^2-32)}{(x+2)(x+4)} = \frac{x(x^2-16)+(2(x^2-16)}{(x+2)(x+4)} =$

$=\frac{(x^2-16)(x+2)}{(x+2)(x+4)} =\frac{(x-4)(x+4)(x+2)}{(x+2)(x+4)} =x-4$