Question

Решите уравнение 1/2х^2+3х+4=0

Answer 1

$\frac{1}{2} x^{2} + 3x + 4=0$
а=1/2, b=3, c=4
D= b²-4ac= 3²-4*1/2*4=9-8=1
$x1= \frac{-b- \sqrt{D} }{2a} = \frac{-3- \sqrt{1} }{2* \frac{1}{2} } = \frac{-4}{1} = -4$
$x2= \frac{-b+ \sqrt{D} }{2a} = \frac{-3+ \sqrt{1} }{2* \frac{1}{2} } = \frac{-2}{1} = -2$
Ответ: -4; -2