Question

Объясните, пожалуйста, подробно пошагово

Answer 1

$\frac{5sin74'}{cos37'*cos53'}= \frac{5cos(90'-74')}{ \frac{1}{2}(cos(37'+53')+cos(37'-53')) }= \frac{10cos16'}{cos90'+cos(-16')} = \frac{10cos16'}{0+cos16'} =$$\frac{10cos16'}{cos16'} =10$