Question

2/π arcsin(4,5-2x+15x в квадрате - 6 х в кубе) = 1/√3 ctg (-46π/3)

решение?

Answer 1

2/π arcsin(4,5-2x+15x^2 - 6 х^3) = 1/√3 ctg (-46π/3)

4,5-2x+15x^2 - 6 х^3 = t

2/π arcsint = 1/√3 ctg (-46π/3)

2/π arcsint = 1/√3* (-1/√3)

2/π arcsint = -1/3

arcsint = -П/6

t = sin(-П/6)

t = -1/2

4,5-2x+15x^2 - 6 х^3 = -0,5

6x^3 - 15x^2 + 2x - 5 = 0

2x(3x^2 + 1) - 5(3x^2 + 1) = 0

(3x^2 + 1)(2x - 5) = 0

3x^2 + 1 = 0    2x - 5 = 0

3x^2 = -1                 х = 2,5

нет решений