Question

Решите уравнение(^-в квадрате)
(4х+1)^=(4х-8)^

Answer 1

$(4x+1)^2=(4x-8)^2 \\ 16x^2+8x+1=16x^2-64x+64 \\ 72x=63 \\ x=0,875$

Ответ: $0,875$

Answer 2

16x^+8x+1=16x^-64x+64
72x=63
x=0.875