Question

5дробьx²-2x-4x-3дробьx²-2x

Answer 1

$\frac{5}{x^2-2x}- \frac{4x-3}{x^2-2x}= \frac{5-(4x-3)}{x^2-2x}=\frac{5-(4x-3)}{x^2-2x}=\frac{5-4x+3}{x^2-2x}=\frac{8-4x}{x^2-2x}= \frac{-4(x-2)}{x(x-2)}= \\ =- \frac{4}{x}$