Question

решите уравнение (х^2-2)(х+3)+(х^2+2)(х-3)=42

Answer 1

$( x^{2} -2)(x+3)+( x^{2} +2)(x-3)=42$
$(x^{3} -2x+3 x^{2} -6)+( x^{3} +2x-3x^2-6)=42$
$2x^{3}-12 =42$
$2x^{3} =54$
$x^{3} =27$
$x=3$