Question

Найдите корень уравнения x+3/3=3-x/8

Answer 1

$\tt\displaystyle\frac{x+3}{3}=\frac{3-x}{8}$

$8(x+3)=3(3-x)$

$8x+24=9-3x$

$8x+3x=9-24$

$11x=-15$

$x=-\tt\displaystyle\frac{15}{11}$

$x=-1\tt\displaystyle\frac{4}{11}$