Question

Решите пожалуйста((((

Answer 1

$\frac{m +2}{m+1} - \frac{8(m^2-1)}{(m-1)(m^2+m+1)} : \frac{4(m+1)}{(m^2+m+1)} = \\ \\ \frac{m+2}{m+1} - \frac{8(m^2-1)(m^2+m+1)}{(m-1)(m^2+m+1)*4(m+1)} = \\ \\ \frac{m+2}{m+1} - \frac{8(m^2-1)}{4(m+1)(m-1)} = \frac{m+2}{m+1} - \frac{2(m^2-1)}{m^2-1} = \\ \\ \frac{m+2}{m+1} -2= \frac{m+2-2(m+1)}{m+1} = \frac{m+2-2m-2}{m+1} = \frac{-m}{m+1}$$\\ \\ \frac{-m}{m+1} * \frac{1}{m} =-\frac{1}{m+1}$