Question

решите уравнение (2х-5)^2-(2х-3)^2=0

Answer 1

(2x-5)^2-(2x-3)^2=0
(4x^2-20x+25)-(4x^2-12x+9)=0
4x^2-20x+25- 4x^2+12x-9=0
-20x+25+12x-9=0
-8x+16=0
-8x=16
x=-16/2
x=-2
Ответ: x=-2