Question

5ый............... . ........

Answer 1

$(- \frac{32x^4}{25y^{3n-2}} )^2:(- \frac{16x^3}{5y^{2n-1}} )^3= \dfrac{32^2\cdot x^8}{25^2\cdot y^{-4}\cdot y^{6n}} \cdot \dfrac{5^3\cdot y^{-3}\cdot y^{6n}}{16^3\cdot x^9} = \frac{1}{20xy^{-1}}$