Question

(x/y+y/x+2)*1/(x+y)^2 при х=√2/3
у=√3/8

Answer 1

$( \frac{x}{y}+ \frac{y}{x}+2)\cdot \frac{1}{(x+y) ^{2} }= \frac{ x^{2} +y ^{2}+2xy }{xy}\cdot \frac{1}{(x+y) ^{2} }= \frac{(x+y) ^{2} }{xy} \cdot \frac{1}{(x+y) ^{2} }= \frac{1}{xy}$
х=√2/3 ;у=√3/8 получим24/√6=4√6