Question

решите уравнения:а)8/25у=3цел.1/5 б)3цел.1/12 -1цел.5/6n=1цел.17/24 в) (7/12+11/30х):7цел.1/4=1/3 г)1/9z+7/18z-11/27z=2цел.1/2 д) а-13/18а=1/3

Answer 1

а. $frac{8}{25}y=3frac{1}{5}$

$frac{8}{25}y=frac{16}{5} \ y=frac{16}{5}:frac{8}{25} \ y=10$

б. 3$3frac{1}{12}- 1frac{5}{6}n=1frac{17}{24}\-1frac{5}{6}n=1frac{17}{24}-3frac{1}{12}\-frac{11}{6}n=frac{41}{24}-frac{37}{12}\-frac{11}{6}n=frac{41}{24}-frac{74}{24}\-frac{11}{6}n=-frac{33}{24}\n=-frac{33}{24}:-frac{11}{6}\ n=frac{3}{4}$

в.$(frac{7}{12}+frac{11}{30}x):7frac{1}{4}=frac{1}{3}\frac{7}{12}+frac{11}{30}x=frac{29}{4}*frac{1}{3}\frac{7}{12}+frac{11}{30}x=frac{29}{12}\frac{11}{30}x=frac{29}{12}-frac{7}{12}\frac{11}{30}x=frac{22}{12}\x=frac{22}{12}:frac{11}{30}\x=5$

г. $frac{1}{9}z+frac{7}{18}z-frac{11}{27}z=2frac{1}{2}\z(frac{1}{9}=frac{7}{18}-frac{11}{27})=frac{5}{2}\z(frac{2}{18}+frac{7}{18}-frac{11}{27})=frac{5}{2}\z(frac{9}{18}-frac{11}{27})=frac{5}{2}\z(frac{27}{54}-frac{22}{54})=frac{5}{2}\zfrac{5}{54}=frac{5}{2}\z=frac{5}{2}:frac{5}{24}\z=12$

д.$a-frac{13}{18}a=frac{1}{3}\a(1-frac{13}{18})=frac{1}{3}\a(frac{18}{18}-frac{13}{18})=frac{1}{3}\afrac{5}{18}=frac{1}{3}\a=frac{1}{3}:frac{5}{18}\a=frac{6}{5}=1frac{1}{5}$