Question

cosx=sin2x решитеееее

Answer 1

cos x = sin 2x
cos x - 2sinx cosx =0
cosx ( 1-2sinx) = 0

cos x= 0
x=π/2 + πn,n ∈ Z

sinx = 1/2
x=(-1)^k × π/6 + πk,k ∈ Z