Question

(/\/6-/\/2)^2*(8+2/\/12) , (/\/3+2)^2-2/\/12 /\/-это корень

Answer 1

$( \sqrt{6} - \sqrt{2} )^2*(8+2 \sqrt{12} )=$

$=(( \sqrt{6})^2 - 2* \sqrt{6*2} +( \sqrt{2} )^2)*(8+2 \sqrt{12} )=$

$=(6-2 \sqrt{12} +2)(8+2 \sqrt{12} )=(8-2 \sqrt{12} )(8+2 \sqrt{12} )=$

$=8^2-(2 \sqrt{12})^2=64-4*12=64-48=16$