Question

Решить неравенство х^2+4x-12>5x

Answer 1

x^2+4x-12>5x

x^2+4x-5x-12>0

x^2-x-12>0

(x+3)(x-4)>0

 

     +                                -                             +

--------------- -3 -------------------- 4 ------------------

 

$(-infty;-3)cup(4;+infty)$

Answer 2

х^2+4x-12>5x

x^2-x-12>0

x=4; x=-3

Ж: (-бесконечности; -3) (4;+бесконечности)