Question

Разложить на множители:
$8x^{3} - 12x^{2}+ 6x-1$

Answer 1

=6x(1-2x)-(1-8x^3)=6x(1-2x)-(1-2x)(1+2x+4x^2)=(1-2x)(6x-1-2x-4x^2)=(1-2x)(-4x^2+4x-1)=-(1-2x)(4x^2-4x+1)=-(1-2x)(2x-1)^2=-(1-2x)(1-2x)^2=-(1-2x)^3