Question

(2х-7)^2-(5+3х)^2=0
Помогите срочноо!!!!!!!

Answer 1

(2х-7)^2-(5+3х)^2=0
(4х^2-28х+49)-(25+30х+9х^2)=0
4х^2-28х+49-25-30х-9х^2=0
-5х^2-58x+24=0
D=3364-4*(-5)*24=3844=62^2
x1=-120/10=-12
x2=-4/-10=0.4