Question

(tво второй +2t-3)-(tво второй -3t+4)=t-1

Answer 1

(t²+2t-3)-(t²-3t+4)=t-1
t²+2t-3-t²+3t-4-t+1=0
t²-t²+2t+3t-t-3-4+1=0
4t-6=0
4t=6
t=$\frac{6}{4} = 1 \frac{2}{4} = 1 \frac{1}{2} = 1,5$