Question

Помогите найти производную y = sin^2 (3x +1) +7

Answer 1

y =sin² (3x+1) +7 ;
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y '=(sin² (3x+1) +7) '=(sin² (3x+1)) ' +(7) ' =2sin(3x+1)*(sin(3x+1))' +0 =
2sin(3x+1)*cos(3x+1)*(3x+1)'  = sin2*(3x+1)*((3x)' +(1))' =sin(6x+2)*(3(x)' +0) =
3sin(6x+2) .