Question

Найдите общий корень уравнений
$(x + 2) (x + 3) (x + 4) = 0$ и $\frac{x^2}{27} = \frac{1}{3}$

Answer 1

$(x + 2) (x + 3) (x + 4) = 0 \\\ \left[\begin{array} x + 2=0 \\ x + 3=0 \\ x + 4=0 \end{array}\right.\Rightarrow \left[\begin{array} x_1 =-2 \\ x_2 =-3 \\ x_3=-4 \end{array}\right.$

$\frac{x^2}{27} = \frac{1}{3} \\\ x^2=27\cdot \frac{1}{3} \\\ x^2=9 \\\ x=\pm3$

Общий корень уравнений равен -3.