Question

$\frac{4x - 3}{3-2x} - \frac{4+5x}{3+2x} - \frac{3+x-10x^{2} }{4 x^{2} - 9}$

Answer 1

(4x-3)/(3-2x)-(4+5x)/(3+2x)+(3+x-10x²)/(3-2x)(3+2x)=
=(12x+8x²-9-6x-12+8x-15x+10x²+3+x-10x²)/(9-4x²)=(8x²-18x)/(9-4x²)=
=2(4x²-9)/(9-4x²)=-2