Question

Найти % состав вещества С2H5OH.

Answer 1

M(C2H5OH) = 2x12 + 6x1 + 1x16 = 24 + 6 + 16 = 46 г/моль
W(C) = [2A(C)/M(C2H5OH)]x100% = [2x12/46]x100% = 52,2 %
W(H) = [6A(H)/M(C2H5OH)]x100% = [6x1/46]x100% = 13 %
W(O) = [A(O)/M(C2H5OH)]x100% = [16/46]x100% = 34,8 %