Question

Как решить данное уравнение

Answer 1

$( \frac{6}{x^{2}-25}+ \frac{1}{5-x})* \frac{x^{2}+10x+25}{5} \\ \\ \frac{6}{(x-5)(x+5)}- \frac{1}{x-5} = \frac{6-(x+5)}{(x-5)(x+5)} = \frac{1-x}{(x-5)(x+5)} \\ \\ \frac{1-x}{(x-5)(x+5)}*\frac{x^{2}+10x+25}{5} = \frac{1-x}{(x-5)(x+5)}*\frac{(x+5)^{2}}{5}= \frac{(1-x)(x+5)}{5(x-5)} = \frac{-x^{2}-4x+5}{5x-25} \\ \frac{x^{2}+4x-5}{25-5x}$