Question

cos (3x-П/6) +1=0-решение

Answer 1

cos(3x-π/6)+1=0
cos(3x-π/6)=-1
3x-π/6=π+2πn, n∈Z
3x=π/6+π+2πn, n∈Z
3x=7π/6+2πn, n∈Z
x=7π/18+2πn/3,n∈Z