Question

найдите tgα, если sinα = 1/√2 и α=(0;П/2)

Answer 1

Решение во вложении.
Meow :)

Answer 2

$1+t g^{2} \alpha = \frac{1}{co s^{2} \alpha } = \frac{1}{ 1-si n^{2} \alpha } = \frac{1}{ 1- ( \frac{1}{ \sqrt{2} } )^{2} } = \frac{1}{ 1- \frac{1}{2} } = \frac{1}{ \frac{1}{ 2 } } = 2$
1+tg²α=2
tg²α=2-1
tg²α=1       ⇒  tgα=√1=1