Question

4х^4-37х^2+9=0
помогите :)

Answer 1

$4 x^4-37 x^{2} +9=0$
$x^{2} =t$
$4t^{2} -37t+9=0$
a=4  b=-37   c=9
D=b²-4ac=37²-4*4*9=1225=35²
$t1= \frac{-b+ \sqrt{D} }{2a} = \frac{37+35}{8} = \frac{72}{8} =9$
$t2= \frac{-b- \sqrt{D} }{2a} = \frac{37-35}{8}= \frac{2}{8} = \frac{1}{4}$
x²=9                   x²=1/4
x=-3                  x=1/2
x=3                    x=-1/2