Question

sin3x-sin7x=(√3)*sin2x

Answer 1

-2sin2xcos5x-√3sin2x=0
-sin2x(2cos5x+√3)=0
sin2x=0⇒2x=πn⇒x=πn/2
cos5x=-√3/2
5x=+-5π/6+2πn⇒x=+-π/6+2πn/5