Question

cos6x=-√3/2дуже срочно

Answer 1

cos6x=-√3/2
6x=+-(arccos(-√3/2))+2πn, n∈Z
6x=+-(π-arccos√3/2)+2πn,n ∈Z
6x=+-(π-π/6)+2πn, n∈Z
6x=+-5π/6+2πn,n∈Z |:6
x=+-5π/36+(1/3)πn, n∈Z