Question

(2b-5)x^2 - 2(b-1)x+3=0

Answer 1

$(2b-5)x^2 - 2(b-1)x+3=0$
$D=4(b-1)^2-4*3*(2b-5)=0$
$4(b^2-2b+1)-12(2b-5)=0$
$4b^2-8b+4-24b+60=0$
$4b^2-32b+64=0$
$b^2-8b+16=0$
$(b-4)^2=0$
$b=4$

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