Question

Раз вложит е на множители:
xy-xz-y+z
km-k-2m+2
3x-3y-2ax+2ay

Answer 1

Xy-Xz-y+z=y(x-1)-z(x-1)=(x-1)(y-z)

Km-k-2m+2=k(m-1)-2(m-1)=(k-2)(m-1)

3x-3y-2ax+2ay=x(3-2a)-y(3-2a)=(x-y)(3-2a)

Answer 2

(ху-хz)-(y-z)=x(y-z)-(y-z)=(y-z)(x-1)

(km-k)-(2m-2)=k(m-1)-2(m-1)=(k-2)(m-1)

(3x-3y)-(2ax-2ay)=3(x-y)-2a(x-y)=(3-2a)(x-y)