Question

решите уравнение
$x( x^{2} +4x+4)=3(x+2)$

Answer 1

$x(x^2+4x+4)=3(x+2)\\\\x(x+2)^2-3(x+2)=0\\\\(x+2)\cdot (x(x+2)-3)=0\\\\(x+2)\cdot (x^2+2x-3)=0\\\\(x+2)(x-1)(x+3)=0\\\\x_1=-2,\; x_2=1,\; x_3=-3$