Question

решите плиз!
(2x-3)в квадрате=9-2(x-3)(x+3)

Answer 1

4$x^{2}$ + 9 -12x = 9-2($x^{2}$ -9)
4$x^{2}$ + 9 -12x= 9-2$x^{2}$ + 18
6$x^{2}$ - 12x-18=0
$x^{2}$ - 2x - 3=0
D=4+12=16
x1=(2-4)/2=-1    x2=(2+4)/2)=3

Answer 2

4х^2-12х+9=9-2(х^2-9)
4х^2-12х+9=9-2х^2+18
6х^2-12х-18=0 /:6
х^2-2х-3=0
D = 4-4*(-3)=4+12=16
х1=2+4/2=3
х2=2-4/2=-1