Question

1+2sinx cosx=0 тригонометрическое уравнение

Answer 1

1+sin2x=0
sin2x=-1
2x--π/2+2πn
x=-π/4+πn

Answer 2

1 + 2sin(x)cos(x) = 0
1 + sin(2x) = 0
sin(2x) = -1
2x = -π/2 + 2πn , n ∈ Z
x = -π/4 + πn , n ∈ Z
Ответ: x = -π/4 + πn , n ∈ Z