Question

1-2sinx*cosx
---------------- +cosx
sinx-cosx
решите пж

Answer 1

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Answer 2

Госы :0
$\frac{1-2sinxcosx}{sinx-cosx} + cosx$
$\frac{1-2sinxcosx+sinxcosx- cos^{2}x }{sinx-cosx} = \frac{1-sinxcosx-cos^{2}x}{sinx-cosx} =$
(1-cos^2x = sin^2x)
$= \frac{sin^{2} x-sinxcosx }{sinx-cosx} = \frac{sinx(sinx-cosx)}{sinx-cosx} = sin x$
Ответ ; sinx