Question

Развязать уравнение 2sin5x+√3=0

Answer 1

$2sin5x+\sqrt3=0\\2sin5x=-\sqrt3\\sin5x=-\frac{\sqrt3}2\\\\ \left[\begin{array}{ccc}5x=-\frac{\pi}3+2\pi n;n\in Z\\\\5x=-\frac{2\pi}3+2\pi n;n\in Z\end{array}\right=\ \textgreater \ \left[\begin{array}{ccc}x=-\frac{\pi}{15}+\frac{2\pi n}5;n\in Z\\\\x=-\frac{2\pi}{15}+\frac{2\pi n}5;n\in Z\end{array}\right$