Question

Найти первообразную f(x)=x+4x^2+7

Answer 1

F(x)=(x^2)/2+4*(x^3)/3+7x

Answer 2

F(x)=$\int\limits {f(x)} \, dx = \int\limits {(x+4 x^{2} +7)} \, dx = \frac{ x^{2}}{2} + \frac{4 x^{3} }{3}+7x+C$