Question

Помогите с решением.

7^log(7√7)27+log(49)16

Answer 1

$7^{ log_{7 \sqrt{7} }27+ log_{49} 16 } =7^{ log_{ 7^{ \frac{3}{2}} }27+ log_{49} 16 } =7^{ \frac{2}{3} log_{ 7 }27+ log_{49} 16 } =$$7^{ log_{ 7 }9+ \frac{1}{2} log_{7} 16 } =7^{ log_{ 7 }9+ log_{7} 4 } = 7^{ log_{7}36 } =36$

Answer 2

log(7√7)27=log(7)9
log(49)16=log(7)4
$7 ^{log(7)9+log(7)4} =7 ^{log(7)9} *7 ^{log(7)4} =9*4=36$