Question

помогите интегралы .............

Answer 1

$\int _0^5\frac{6}{\sqrt{3x+1}}dx=6\cdot \frac{1}{3}\cdot \frac{1}{2\sqrt{3x+1}}|_0^5=\frac{1}{\sqrt{16}}-\frac{1}{\sqrt1}=\frac{1}{4}-1=-\frac{3}{4}\\\\P.S.\; \; \int \frac{dx}{\sqrt{ax+b}}=\frac{1}{a}\cdot \frac{1}{2\sqrt{ax+b}}+C$