Question

помогитеее вычислить
sin пи/6+sin(arccos1\4)

Answer 1

sin пи/6+sin(arccos1\4)=1/2+√(1-(1/4)²)=1/2+√15/4=(2+√15)/4

Answer 2

$sin\frac{ \pi }{6} +sin(arccos \frac{1}{4} )=[tex] \frac{1}{2} + \frac{ \sqrt{15} }{4} = \frac{2+ \sqrt{15} }{4}$[/tex]
$arccos \frac{1}{4} = \alpha$
$cos \alpha = \frac{1}{4}$
$sin^2 \alpha =1-cos^2 \alpha =1- \frac{1}{16} = \frac{15}{16}$
$sin \alpha = \frac{ \sqrt{15} }{4}$