Question

-24ab-(4a-3b)^2 при а=корень 8,b=корень 3

Answer 1

-24ab-16a²+24ab-9b²=-16a²-9b²=-16*8-9*3=-128-27=-155

Answer 2

$... = -24ab - ( 16a^{2} - 24ab + 9b^{2} ) = -24ab - 16a^{2} + 24ab - 9b^{2} =$ $- 16a^{2} - 9b^{2} = - ( 16a^{2} + 9b^{2} ) = - ((16 * (\sqrt{8} )^2 + 9 * (\sqrt{3} )^2) =$ $= -(16*8+9*3) = -(128+27) = - 155$