Question

lim x стремится к-3 x^2-9/4x+12

Answer 1

$\lim_{x \to -3} \frac{x^2-9}{4x+12}= \lim_{x \to -3} \frac{(x-3)(x+3)}{4(x+3)}=\lim_{x \to -3}\frac{x-3}{4}=\frac{-3-3}4=-\frac{6}{4}=-\frac{3}2$