Question

3tg^2pi/6+√2sinsinpi/4
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Answer 1

$3tg^2 \frac{ \pi }{6} + \sqrt{2} sin \frac{ \pi }{4} =3* (\frac{ \sqrt{3} }{3})^2+ \sqrt{2} * \frac{ \sqrt{2} }{2} =3* \frac{1}{3} +1=1+1=2$