Question

sin3x-cos3x=-корень2

Answer 1

sin3x-sin(π/2-3x)=-√2
2sin(3x-π/4)cosπ/4=-√2
2*√2/2sin(3x-π/4)=-√2
sin(3x-π/4)=-1
3x-π/4=-π/2+2πn
3x=-π/2+π/4+2πn
3x=-π/4+2πn
x=-π/12+2πn/3