Question

найти производную
$y=\frac{18}{4x+1}$

Answer 1

$y'=( \frac{18}{4x+1} )'= \frac{(18)'*(4x+1)-(4x+1)'*18}{(4x+1)^2} = \\ \\ = \frac{-4*18}{(4x+1)^2} =- \frac{72}{(4x+1)^2} .$