Question

найти интеграл (2*x-5)*sin(x)

Answer 1

U=2x-5
dU=2dx
dV=sinxdx
V=-cosx
=(2x-5)(-cosx)-$\int {(-cosx)} \, 2dx$=-(2x-5)cosx+2$\int {cosx} \, dx$=-(2x-5)cosx+2sinx+C