Question

32 баллушка ^..^ ))))

Answer 1

$\int _{-1}^0(2x+1)^4dx=\frac{1}{2}\cdot \frac{(2x+1)^5}{5}|_{-1}^0=\frac{1}{10}\cdot (1^5-(-1)^5)=\frac{1}{10}\cdot (1+1)=\frac{1}{5}\\\\\\P.S.\int (ax+b)^{n}dx=\frac{1}{a}\cdot \frac{(ax+b)^{n+1}}{n+1}+C$