Question

Решите неравенство log_3(x^2-2x)>1

Answer 1

log_3(x`2-2x)>1
3`1>x`2-2x
3>x`2-2x
x`2-2x-3>0

D=4-4(-3) = 16
`D = 4
x1 = -1 
x2 = 3
Ответ: x~(-s;-1)~(3;+s)