Question

а это верно сделала? ))

Answer 1

$\lim_{x \to \infty} \frac{3x^{2}-4x+5}{x^{2}+2x+3}=\lim_{x \to \infty} \frac{x^{2}(3- \frac{4}{x} + \frac{5}{x^{2}}) }{x^{2}(1+ \frac{2}{x} + \frac{3}{x^{2}})}= \lim_{x \to \infty} \frac{3- \frac{4}{x} + \frac{5}{x^{2}}}{1+ \frac{2}{x} + \frac{3}{x^{2}}} = 3$

Answer 2

(lim(x⇒+∞)(3x²-4x+5)/(x²+2x+3)=
=lim(x⇒+∞)(3x²/x²-4x/x²+5/x²)/(x²/x²+2x/x²+3/x²)=3/1=3.