Question

(3x+1)(2x-3)+4(x-2)=(4-3x)

Answer 1

$(3x+1)(2x-3)+4(x-2)=4-3x \\ 6 x^{2} -9x+2x-3+4x-8=4-3x \\ 6 x^{2} = 15\\ x^{2} =2.5 \\ x=1.58$

Answer 2

$(3x+1)(2x-3)+4(x-2)=(4-3x)\\6 x^{2} -9x+2x-3+4x-8=4-3x\\6 x^{2} -9x+2x+4x+3x=4+8+3\\6 x^{2} =15\\x=+- \sqrt{ \frac{15}{6} } \\x=+- \sqrt{2.5}$